2x^2-18x-45=0

Solution for 2x^2-18x-45=0 equation:

2x^2-18x-45=0

a = 2; b = -18; c = -45;
Δ = b2-4ac
Δ = -182-4·2·(-45)
Δ = 684
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{684}=\sqrt{36*19}=\sqrt{36}*\sqrt{19}=6\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{19}}{2*2}=\frac{18-6\sqrt{19}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{19}}{2*2}=\frac{18+6\sqrt{19}}{4}
$